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Calculate the self-inductance of an air-...

Calculate the self-inductance of an air-cored solenoid 50 cm long and 2 cm radius if the number of turns in the coil of solenoid is 400.

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To calculate the self-inductance of an air-cored solenoid, we can use the formula: \[ L = \frac{\mu_0 n^2 A}{l} \] Where: - \( L \) = self-inductance (in Henry) - \( \mu_0 \) = permeability of free space = \( 4\pi \times 10^{-7} \, \text{H/m} \) - \( n \) = number of turns per unit length (in turns/meter) ...
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Knowledge Check

  • What is the self-inductance of an air-core solenoid 1 m long, diameter 0.05 m, if it has 500 turns? Take, pi^(2)=10 .

    A
    `3.15xx10^(-4)H`
    B
    `4.8xx10^(-4)H`
    C
    `5xx10^(-4)H`
    D
    `6.25xx10^(-4)H`
  • The self-inductance of an air core solenoid of 100 turns iz 1 mH. The self-inductance of another solenoid of 50 turns (with the same length and cross sectional area) with a core having relative permeability 500 is

    A
    125 mH
    B
    24 mH
    C
    60 mH
    D
    30 mH
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