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An emf of 40 kV is induced in the second...

An emf of 40 kV is induced in the secondary of car spark coil when the current in primary changes from 5A to 2A in `20 mus`. Calculate the mutual inductance between the primary and secondary windings of this coil.

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To solve the problem, we need to calculate the mutual inductance (M) between the primary and secondary windings of a car spark coil using the given information. ### Step-by-Step Solution: 1. **Identify the given values**: - Induced EMF (E) = 40 kV = 40,000 V = \(40 \times 10^3\) V - Initial current in primary (I1) = 5 A - Final current in primary (I2) = 2 A ...
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