A conducting square loop of side 10 cm i...

A conducting square loop of side 10 cm is placed in a region of uniform magnetic field 0.5 T as shown in the figure. Calculate the work done in slowly moving the loop out of the field in 2 seconds with a speed of `0.05 m s^(-1)`. The resistance of loop is 10 `Omega`.

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The correct Answer is:

`1.25 xx 10^(-6)` J

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