Current in an LR circuit attains one-fourth of its steady state value in 2 seconds. Calculate time constant for this circuit.

The current in an L-R circuit builds upto 3//4th of its steady state value in 4sec . Then the time constant of this circuit is

The current in a LR circuit builds up to (3)/(40th of its steady state value ion 4s . The time constant. Of this circuit is

The current in a LR circuit builds up to 3/4 th of its steady state value in 4s. The time constant of this circuit is

The current in a LR circuit builds up to (3)/(4)th of its steady state value in 4s . The time constant of this circuit is

The value of time constant for the given circuit is

In an LR-circuit the current attains one-third of its final steady value in 5s. What is the time-constant of the circuit ? (log_(2) = 0.405)

The current in an RL circuit builds up to one-third of its steady-state value in 5.00 s. Find the inductive time constant.

Time constant of LR circuit will be

The current in a discharging LR circuit without the battery drops from 2.0 A to 0.10 s. (a) find the time constant of the circuit. (b) if the inductance of the circuit is 4.0 H, what is its resistance?