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A 100 turns coil of area of cross sectio...

A 100 turns coil of area of cross section `200 cm^(2)` having `2 Omega` resistance is held perpendicular to a magnetic field of 0.1 T. If it is removed from the magnetic field in one second, the induced charge produced in it is

A

0.2 C

B

2C

C

0.1C

D

1C

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The correct Answer is:
To solve the problem, we need to calculate the induced charge produced in a coil when it is removed from a magnetic field. We will follow these steps: ### Step 1: Calculate the change in magnetic flux (ΔΦ) The magnetic flux (Φ) through a coil is given by the formula: \[ \Phi = B \cdot A \cdot \cos(\theta) \] Where: - \(B\) is the magnetic field strength (0.1 T), - \(A\) is the area of the coil, - \(\theta\) is the angle between the magnetic field and the normal to the coil's surface (90 degrees here, so \(\cos(90^\circ) = 1\)). Given: - The area \(A = 200 \, \text{cm}^2 = 200 \times 10^{-4} \, \text{m}^2 = 0.02 \, \text{m}^2\). Now, the initial magnetic flux when the coil is in the magnetic field is: \[ \Phi_{\text{initial}} = B \cdot A = 0.1 \, \text{T} \cdot 0.02 \, \text{m}^2 = 0.002 \, \text{Wb} \] When the coil is removed from the magnetic field, the final magnetic flux is: \[ \Phi_{\text{final}} = 0 \, \text{Wb} \] Thus, the change in magnetic flux (ΔΦ) is: \[ \Delta \Phi = \Phi_{\text{final}} - \Phi_{\text{initial}} = 0 - 0.002 = -0.002 \, \text{Wb} \] ### Step 2: Calculate the induced EMF (E) According to Faraday's law of electromagnetic induction, the induced EMF (E) is given by: \[ E = -\frac{d\Phi}{dt} \] For a coil with \(N\) turns, the induced EMF is: \[ E = -N \cdot \frac{\Delta \Phi}{\Delta t} \] Where: - \(N = 100\) (number of turns), - \(\Delta t = 1 \, \text{s}\). Substituting the values: \[ E = -100 \cdot \frac{-0.002}{1} = 0.2 \, \text{V} \] ### Step 3: Calculate the current (I) Using Ohm's law, the current (I) can be calculated as: \[ I = \frac{E}{R} \] Where \(R = 2 \, \Omega\) (resistance of the coil). Substituting the values: \[ I = \frac{0.2}{2} = 0.1 \, \text{A} \] ### Step 4: Calculate the induced charge (Q) The induced charge (Q) can be calculated using the formula: \[ Q = I \cdot t \] Where \(t = 1 \, \text{s}\). Substituting the values: \[ Q = 0.1 \, \text{A} \cdot 1 \, \text{s} = 0.1 \, \text{C} \] ### Final Answer The induced charge produced in the coil is \(0.1 \, \text{C}\). ---

To solve the problem, we need to calculate the induced charge produced in a coil when it is removed from a magnetic field. We will follow these steps: ### Step 1: Calculate the change in magnetic flux (ΔΦ) The magnetic flux (Φ) through a coil is given by the formula: \[ \Phi = B \cdot A \cdot \cos(\theta) \] Where: ...
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MODERN PUBLICATION-ELECTROMAGNETIC INDUCTION-COMPETITION FILE (MULTIPLE CHOICE QUESTIONS) (JEE (Main) & Other State Boards for Engineering Entrance)
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  9. When current in a coil changes from 5 A to 2 A in 0.1 s, average volta...

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