When current in a coil changes from 5 A to 2 A in 0.1 s, average voltage of 50 V is produced. The self - inductance of the coil is :

Options

A. 0.67 H
B. 1.67 H
C. 3H
D. 6 H

Answer

B

Explanation

`phi= Li`
`(dphi)/(dt)= L(di)/(dt)`
`-V= +L(di)/(dt)`
`-50 = L((2-5)/(0.1))`
`L= (5)/(3)H`
Self-inductance L = 1.67 H