Home
Class 12
PHYSICS
The charge on a parallel plate capacitor...

The charge on a parallel plate capacitor varies as `=q_0 cos 2pi ft`. The plates are very large and close together (area=a,separation=d). Neglecting the edge effects, find the displacement current through the capacitor.

Text Solution

Verified by Experts

Given , charge
` q= q_0 cos 2 pi v t `
conduction current is given by
`i_c = ( dq )/( dt ) = (d )/(dt ) ( q_0 cos 2 pi v t )`
`=- q_0 ( 2pi v ) sin 2 pi v t `
since displacement current `,i_d =i_c `
` therefore i_d =- q_0 ( 2pi v ) sin 2 pi v t `
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC WAVES

    MODERN PUBLICATION|Exercise NCERT FILE ( NCERT EXEMPLAR PROBLEMS SUBJECTIVE QUESTIONS ) ( SHORT ANSWER TYPE QUESTIONS )|7 Videos

  • ELECTROMAGNETIC WAVES

    MODERN PUBLICATION|Exercise HIGHER ORDER THINKING SKILS & ADVANCED LEVEL|5 Videos

  • ELECTROMAGNETIC WAVES

    MODERN PUBLICATION|Exercise NCERT FILE (NCERT EXEMPLAR PROBLEMS OBJECTIVE QUESTIONS)|13 Videos

  • ELECTROMAGNETIC INDUCTION

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST FOR BOARD EXAMINATION|14 Videos

  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    MODERN PUBLICATION|Exercise Chapter Practice Test|9 Videos

Similar Questions

Explore conceptually related problems

The charge on a parallel plate capacitor varies as q = q_(0) "cos" 2 pit . The plates are very large and close together (area = A, separation = d). The displacement current through the capacitor is

The charge of a parallel plate capacitor is varying as q = q0 sin omega t. Then find the magnitude of displacement current through the capacitor. (Plate Area = A, separation of plates = d)

There is a parallel plate capacitor of capacitances 2.0muF . The voltage between the plates of parallel plate capacitor is changing at the rate of 6.0Vs^-1 . What is the displacement current in the capacitor?

Area of a parallel plate capacitor of capacitance 2F and separation between the plates 0.5cm will be

In a parallel plate capacitor with plate area A and charge Q, the force on one plate because of the charge on the other is equal to

A parallel plate capacitor 20 muF is being charged by a voltage source whose potential is changing at the rate of 3 V/s. The conduction current through the connecting wires, and the displacement current through the plates of the capacitor, would be, respectively:

The charges appearing on inner surfaces of a parallel plate capacitor are q_( i and )q_(2) . The charges appearing on outer surfaces of the capacitor are equal.Find the potential difference between plates of the capacitor if capacitances is C.

A parallel plate capacitor with plate area A and plate separation d, is charged by a steady current I. Let a plane surface of area A//3 parallel to the plates and situated symmetrically between the plates. What is the displacement current through this area?