A parallel plate capacitor having capacitance of 300`p`F. The capacitor is connected to a 300 V supply with an angular frequency of 300 rad/s.
(a) What is the rms value of conduction current?
(b) Find the peak value of displacement current.

Explanation

To solve the problem step by step, we will break it down into two parts: (a) finding the RMS value of the conduction current and (b) finding the peak value of the displacement current.

### Step-by-Step Solution

**Given:**
- Capacitance, \( C = 300 \, \text{pF} = 300 \times 10^{-12} \, \text{F} \)
- Voltage, \( V_{\text{rms}} = 300 \, \text{V} \)
- Angular frequency, \( \omega = 300 \, \text{rad/s} \)
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