An electromagnetic wave going through vacuum is described by
` E= E_0 sin(kx- omega t), B=B_0sin(kx-omega t)`.
Then

Options

A. `E_0 omega = B_0 k`
B. `E_0 k = B_0 omega `
C. `E_0 B_0 = omegak`
D. `E_0 B_0 = omega //k`

Answer

B

Explanation

Speed of the wave is given by v =`(omega )/(k ) `
Speed of the electromagnetic wave is given by
`v= (E_0)/(B_0)`
Equating both the above relations we get the following:
`(E_0 )/(B_0)=(omega)/(k )`
`impliesE_0 k = B_0 omega `