Home
Class 12
PHYSICS
Separation between the slits in Young's ...

Separation between the slits in Young's double-slit experiment is d and screen is placed at a distance D from the slits to observe the interference pattern. Wavelength of light used is `lambda`. Find the distance of point from centre of screen where intensity falls to (i) half the maximum and (ii) one-fourth of the maximum.

Text Solution

AI Generated Solution

To solve the problem of finding the distance from the center of the screen where the intensity falls to half and one-fourth of the maximum in Young's double-slit experiment, we can follow these steps: ### Step 1: Understand the Setup In Young's double-slit experiment, we have: - Separation between the slits: \( d \) - Distance from the slits to the screen: \( D \) - Wavelength of light used: \( \lambda \) ...
Promotional Banner

Topper's Solved these Questions

  • WAVE OPTICAL

    MODERN PUBLICATION|Exercise PRACTICE PROBLEMS (1)|23 Videos

  • WAVE OPTICAL

    MODERN PUBLICATION|Exercise PRACTICE PROBLEMS (2)|10 Videos

  • SEMICONDUCTOR ELECTRONICS METERIALS DEVICES AND SIMPLE CIRCUITS

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST FOR BOARD EXAMINATION|12 Videos

Similar Questions

Explore conceptually related problems

In a Young's double slit interference experiment the fringe pattern is observed on a screen placed at a distance D from the slits. The slits are separated by a distance d and are illuminated by monochromatic light of wavelength lamda . Find the distance from the central point where the intensity falls to (a) half the maximum, (b) one fourth of the maximum.

In Young's double-slit experiment , d is separation between the slits. Separation between plane of the slits and screen is D. Wavelength of light used is lambda . Number of fringes per unit distance on the screen is

In Young's double-slit experiment, the intensity at a point P on the screen is half the maximum intensity in the interference pattern. If the wavelength of light used is lambda and d is the distance between the slits, the angular separation between point P and the center of the screen is

In a double slit experiment, the separation between the slits is d and distance of the screen from slits is D. If the wavelength of light used is lambda and I is theintensity of central bright fringe, then intensity at distance from central maximum is

The two slits in Young's double slit experiments are separted by a distance of 0.03 mm . When light of wavelength 5000 Å falls on the slits, an interference pattern is produced on the screen 1.5 m away. Find the distance of fourth bright fringe from the central maximum.

In a double slit experiment the separation between the slits is d and distance of screen from slits is D. If the wavelenth of light used is lamda and I is the intensity of central bright fringe, then intensity at distance x from central maximum is given by

In a Young's double slit experiment sources of equal intensites are used. Distance between slits is d and wavelength of light used is lambda(lambdaltltd) . Angular separation of the nearst points on either side of central maximum where intensities become half of the maximum vlaue is -

In Young's double-slit experiment, the separation between the slits is halved and the distance between the slits and the screen in doubled. The fringe width is

The two slits in Young's double slit experiment are illuminated by two different sodium lamps emitting light of the same wavelength. No interference pattern will be observed on the screen.