If two slits in Young's double-slit experiment have width ratio 9:1, deduce the ratio of intensity at maxima and minima in the interference pattern.

Explanation

To solve the problem of finding the ratio of intensity at maxima and minima in Young's double-slit experiment when the width ratio of the slits is given as 9:1, we can follow these steps:

### Step 1: Define the Widths of the Slits
Let the width of the first slit \( W_1 = 9x \) and the width of the second slit \( W_2 = x \). This gives us the width ratio \( \frac{W_1}{W_2} = \frac{9}{1} \).

### Step 2: Relate Widths to Intensities
In the case of Young's double-slit experiment, the intensity of light from each slit is proportional to the square of the width of the slit. Therefore, we can express the intensities as:
- Intensity from slit 1: \( I_1 \propto W_1^2 = (9x)^2 = 81x^2 \)
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