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White light incident perpendicular on a ...

White light incident perpendicular on a soap film gets reflected . It has an interference maximum at `5800 Å` and a minimum at `4200 Å` in a visible spectrum. If there is no minimum in between the two bands, find the thickness of the soap film. Take refractive index of film = `4//3`.

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To find the thickness of the soap film given the conditions of interference maxima and minima, we can follow these steps: ### Step 1: Identify the given values - Wavelength of interference maximum, \( \lambda_1 = 5800 \, \text{Å} = 5800 \times 10^{-10} \, \text{m} \) - Wavelength of interference minimum, \( \lambda_2 = 4200 \, \text{Å} = 4200 \times 10^{-10} \, \text{m} \) - Refractive index of the soap film, \( \mu = \frac{4}{3} \) ### Step 2: Write the conditions for maxima and minima ...
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