A thin glass plate of refractive index 1.5 is introduced in the path of one of the interfering beam. As a result, the central bright fringe moves to a position previously occupied by the fifth bright fringe. If the wavelength of beam is `6.2 xx 10^(-5) cm`, calculate the thickness of glass plate.

Explanation

To solve the problem, we need to calculate the thickness of the glass plate that causes the central bright fringe to shift to the position of the fifth bright fringe in an interference pattern. Here's a step-by-step solution:

### Step 1: Understand the Problem
When a thin glass plate is introduced in the path of one of the interfering beams, it changes the optical path length. The central bright fringe shifts to the position of the fifth bright fringe, indicating a change in path difference.

### Step 2: Define the Parameters
- Refractive index of glass plate, \( \mu = 1.5 \)
- Wavelength of the beam, \( \lambda = 6.2 \times 10^{-5} \, \text{cm} = 6.2 \times 10^{-7} \, \text{m} \) (conversion to meters)
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