Light of wavelength 500 nm falls normally on a slit of width `1 mu m` producing Fraunhofer diffraction pattern on a screen. Calculate the angular position of the first minimum and the angular width of the central maximum.

Explanation

To solve the problem, we need to calculate the angular position of the first minimum and the angular width of the central maximum for a single slit diffraction pattern.

### Given Data:
- Wavelength of light, \( \lambda = 500 \, \text{nm} = 500 \times 10^{-9} \, \text{m} \)
- Width of the slit, \( a = 1 \, \mu m = 1 \times 10^{-6} \, \text{m} \)

### Step 1: Calculate the angular position of the first minimum

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