A laser operates at a frequency of `5 xx 10^(14) Hz`. If the laser has an aperture of 10 mm, what will be the angular spread?

Explanation

To solve the problem of finding the angular spread of a laser beam operating at a frequency of \(5 \times 10^{14} \, \text{Hz}\) with an aperture of \(10 \, \text{mm}\), we can follow these steps:

### Step 1: Identify the given values
- Frequency of the laser, \( \nu = 5 \times 10^{14} \, \text{Hz} \)
- Aperture width, \( a = 10 \, \text{mm} = 10 \times 10^{-3} \, \text{m} \)

### Step 2: Calculate the wavelength (\( \lambda \))
Using the relationship between the speed of light (\( c \)), frequency (\( \nu \)), and wavelength (\( \lambda \)):
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