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Two thin glass plates are placed paralle...

Two thin glass plates are placed parallel to each other such that distance between them is very small. Each glass plate reflects 25% of incident energy and transmits remaining 75% Light beam is incident on this system. Consider the interference of two light beams obtained after one reflection from each glass plate. Calculate ratio of the maximum to minimum intensity.

Text Solution

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To solve the problem, we need to calculate the ratio of maximum to minimum intensity of light after interference from two thin glass plates. Here’s a step-by-step breakdown of the solution: ### Step 1: Define the Incident Intensity Let the intensity of the incident light beam be \( I \). ### Step 2: Calculate Reflected and Transmitted Intensities - **Reflection from the first plate**: The first plate reflects 25% of the incident intensity, so the reflected intensity \( I_1 \) is: \[ ...
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Knowledge Check

  • Two polaroids are kept crossed to each other . If one of them is rotated an angle 60^@ , the percentage of incident light now transmitted through the system is

    A
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    B
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    B
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