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In Young's double-slit experiment, two c...

In Young's double-slit experiment, two coherent source are used. Intensity of one of the sources is I but for the other it is slightly different `I + dI`. Show that intensity at the minima is approximately `((delta I)^2)/(4 I)`.

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To solve the problem, we need to find the intensity at the minima in Young's double-slit experiment when the intensities of the two coherent sources are slightly different. Let's denote the intensity of the first source as \( I_1 = I \) and the intensity of the second source as \( I_2 = I + dI \). ### Step-by-Step Solution: 1. **Write the formula for resultant intensity**: The resultant intensity \( I_{min} \) at any point due to two coherent sources can be expressed as: \[ I_{min} = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi ...
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