The ratio of amplitude of two waves producing interference pattern is 1 : 4. Find `I_("max")` to `I_("min")` and fringe visiblity.

If the ratio of the intensities of two waves producing interference is 9:4, then the ratio of the resultant maximum and minimum intensities will be

Two coherent sources of light of intensity ratio beta produce interference pattern. Prove that in the interferencepattern (I_(max) - I_(min))/(I_(max) + (I_(min))) = (2 sqrt beta)/(1 + beta) where I_(max) and I_(min) are maximum and mininum intensities in the resultant wave.

Two coherent light sources having intensity in the ratio 2x produce an interference pattern. The ratio (I_(max)-I_(min))/(I_(max)+I_(min)) will be :

Two coherent sources of intensity ratio alpha interface . In interference pattern (I_("max") - I_("min"))/(I_("max") + I_("min")) =

If the ratio of the amplitudes of two interfering wave is 4:3, then the ratio of the maximumum and minimum intensities in the interference pattern is

The intensity ratio of two coherent sources of light is p. They are interfering in some region and produce interference patten. Then the fringe visibility is