Light of wavelength `6000 Å` is incident normally on single slit of width 0.23 mm. Find the angular spread between the central maxima and second-order maxima of diffraction pattern.

Explanation

To find the angular spread between the central maxima and the second-order maxima of a single slit diffraction pattern, we can follow these steps:

### Step 1: Understand the formula for maxima in single slit diffraction
The condition for the position of the maxima in a single slit diffraction pattern is given by:
\[ b \sin \theta = (2n + 1) \frac{\lambda}{2} \]
where:
- \( b \) = width of the slit
- \( \theta \) = angle of the maxima
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