Light of wavelength `6000 Å` is incident normally on a single slit of width 0.03 mm. Find the width of the central maxima on the screen which is at a distance 1.5 m away from the slit. What will be the width if the apparatus is immersed in water of refractive index 1.33?

Explanation

To solve the problem of finding the width of the central maxima in a single slit diffraction pattern, we can follow these steps:

### Step 1: Identify the given values
- Wavelength of light, \( \lambda = 6000 \, \text{Å} = 6000 \times 10^{-10} \, \text{m} \)
- Width of the slit, \( b = 0.03 \, \text{mm} = 0.03 \times 10^{-3} \, \text{m} \)
- Distance from the slit to the screen, \( d = 1.5 \, \text{m} \)

### Step 2: Use the formula for the width of the central maxima
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