Two identical coherent sources are used to perform interference experiment. Intensity of light at the point of maxima is found to be `I_0`. If one of the slits is closed, then what will be intensity of light at the same point?

Options

A. `I_0`
B. `4I_0`
C. `I_0//4`
D. `2I_0`

Answer

C

Explanation

Let I be the intensity of single source, then at the point of maxima resultant intensity will be four times of the intensity of single source, hence we can write the following:
`4I = I_0 implies I = I_0//4`.
If one of the slits is covered, then no interference will take plance and intensity everywhere will be same as intensity of the single source, hence `I = I_0//4`.