Lights of wavelength 550 nm falls normally on a slit of width k`22.0 xx 10^(-5) cm`. The angular position of the central maximum will be (in radian) :

Options

A. `pi/4`
B. `pi/8`
C. `pi/12`
D. `pi/6`

Answer

B

Explanation

If angular position of second minima from central maxima is `theta` then
`sin theta = (3 lambda)/(2a) = (3 xx 550 xx 10^(-9))/(2 xx 22 xx 10^(-7)) = 0.375 implies theta = 22^@`
`implies theta = (pi)/8` rad.