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In an interference experiment the ratio ...

In an interference experiment the ratio of amplitudes of coherent waves is `a_1/a_2=1/3` The ratio of maximum and minimum intensities of fringes is …………..

A

9

B

4

C

18

D

2

Text Solution

Verified by Experts

The correct Answer is:
B
Given ratio of amplitude : `(a_1)/(a_2) = 1/3`
`(I_("max"))/(I_("min")) = ((a_1 + a_2)^2)/((a_1 + a_2)^2) = ((1 + 3)^2)/((1-3)^2) = 4`.
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