Calculate the energy in eV for each photon for light of wavelength `4950Å` . Take `h=6.6xx10^(-34)J-s`

Explanation

To calculate the energy of each photon for light of wavelength \(4950 \, \text{Å}\), we can use the formula that relates energy to wavelength:

\[ E = \frac{hc}{\lambda} \]

Where:
- \(E\) is the energy of the photon,
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