Home
Class 12
PHYSICS
The maximum kinetic energy of electrons ...

The maximum kinetic energy of electrons in a photocell is 5.5 eV. Calculate the stopping potential .

Text Solution

AI Generated Solution

To solve the problem of calculating the stopping potential given the maximum kinetic energy of electrons in a photocell, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship between kinetic energy and stopping potential**: The maximum kinetic energy (K.E.) of the electrons emitted from the photocell is related to the stopping potential (V_s) by the equation: \[ K.E. = e \cdot V_s ...
Promotional Banner

Topper's Solved these Questions

  • DUAL NATURE OF RADIATION AND MATTER

    MODERN PUBLICATION|Exercise PRACTICE PROBLEMS - 1|4 Videos
  • DUAL NATURE OF RADIATION AND MATTER

    MODERN PUBLICATION|Exercise PRACTICE PROBLEMS - 2|10 Videos
  • CURRENT ELECTRICITY

    MODERN PUBLICATION|Exercise Chapter Practice Test|15 Videos
  • ELECTRIC CHARGES AND FIELDS

    MODERN PUBLICATION|Exercise Chapter Practice Test|15 Videos

Similar Questions

Explore conceptually related problems

Assertion: If the maximum kinetic energy of electrons emitted by a photo cell is 5 eV, then the stopping potential is 5 V. Reason: Stopping potential for fastest photoelectrons is numerically equal to their kinetic energy.

The maximum kinetic energy of the photoelectrons is related to the stopping potential (v_(0)) thorugh the relation

The maximum kinetic energy of a photoelectron is 3 eV. What is its stopping potential ?

Assertion: Stopping potential depends upon the frequency of incident light but is independent of the intensity of the light. Reason :The maximum kinetic energy of the photoclectrons is proportional to stopping potential

The maximum energy of the electrons released in photocell is independent of -

In a photoelectric experiment, a monochromatic light is incident on the metal plate A. It was observed that with V = 5 "volt" , the maximum kinetic energy of photoelectrons striking plate B was 1 eV . The polarity of the applied potential difference was as shown in figure (a). With polarity of the applied potential difference reversed (as shown in figure (b)) and frequency of incident light doubled, it was observed that in saturation state, the kinetic energy of electrons striking plate B ranged between 5 eV to 20 eV. Find the work function of metal used in plate A.

MODERN PUBLICATION-DUAL NATURE OF RADIATION AND MATTER -CHAPTER PRACTICE TEST
  1. The maximum kinetic energy of electrons in a photocell is 5.5 eV. Calc...

    Text Solution

    |

  2. Define the term 'stopping potential' in relation to photoelectric effe...

    Text Solution

    |

  3. How the kinetic energy of ejected electrons depends on the intensity o...

    Text Solution

    |

  4. A proton and an electron have same velocity. Which one has greater de ...

    Text Solution

    |

  5. What would be the de Broglie wavelength of an electron possessing 100 ...

    Text Solution

    |

  6. Find the momentum of a wavelength 0.03Å if planck's constant is h.

    Text Solution

    |

  7. (a) Why photoelectric effect cannot be explained on the basis of wave ...

    Text Solution

    |

  8. The graph shows variation of stopping potential V(0) versus frequency ...

    Text Solution

    |

  9. Plot a graph showing variation of de-broglie wavelength lambda versus ...

    Text Solution

    |

  10. A photon and an elecron have the same de Broglie wavelength. Which has...

    Text Solution

    |

  11. Show that the do Broglie wavelength lamda of an electron of energy ...

    Text Solution

    |

  12. Define threshold frequency and work function of a metal. Show that do ...

    Text Solution

    |

  13. Light of intensity I and frequency nu is incident on a photosensitive ...

    Text Solution

    |

  14. Write the three characteristic features in photoelectric effect which...

    Text Solution

    |

  15. In a plot of photoelectric current versus anode potential, how does ...

    Text Solution

    |

  16. An electron microscope uses electrons accelerated by a voltage of 50kV...

    Text Solution

    |