A UV light of wavelength 320 nm is incident on a photosensitive surface and photoelectrons are emitted from it . The stopping potential is 0.48 V. Find
(i) the energy of each incident photon.
(ii) maximum kinetic energy of a photoelectron.
(iii) work function of surface.

Explanation

To solve the problem step by step, we will break it down into three parts as per the question.

### Given Data:
- Wavelength of UV light, \( \lambda = 320 \, \text{nm} = 320 \times 10^{-9} \, \text{m} \)
- Stopping potential, \( V_s = 0.48 \, \text{V} \)

### (i) Energy of Each Incident Photon

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