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A metal having work function of 2 eV is ...

A metal having work function of 2 eV is placed inside a magnetic field. Light of wavelength 400 nm is incident on this metal , and it is found that emitted electrons go around in circular paths . Maximum possible radius is found to be 25 cm . Find the magnitude of magnetic field strength.

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To solve the problem step by step, we will follow these steps: ### Step 1: Calculate the Energy of the Incident Light The energy of the incident light can be calculated using the formula: \[ E = \frac{hc}{\lambda} \] Where: ...
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MODERN PUBLICATION-DUAL NATURE OF RADIATION AND MATTER -CHAPTER PRACTICE TEST
  1. A metal having work function of 2 eV is placed inside a magnetic field...

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  2. Define the term 'stopping potential' in relation to photoelectric effe...

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  3. How the kinetic energy of ejected electrons depends on the intensity o...

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  4. A proton and an electron have same velocity. Which one has greater de ...

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  5. What would be the de Broglie wavelength of an electron possessing 100 ...

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  6. Find the momentum of a wavelength 0.03Å if planck's constant is h.

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  7. (a) Why photoelectric effect cannot be explained on the basis of wave ...

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  8. The graph shows variation of stopping potential V(0) versus frequency ...

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  9. Plot a graph showing variation of de-broglie wavelength lambda versus ...

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  10. A photon and an elecron have the same de Broglie wavelength. Which has...

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  11. Show that the do Broglie wavelength lamda of an electron of energy ...

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  12. Define threshold frequency and work function of a metal. Show that do ...

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  13. Light of intensity I and frequency nu is incident on a photosensitive ...

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  14. Write the three characteristic features in photoelectric effect which...

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  15. In a plot of photoelectric current versus anode potential, how does ...

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  16. An electron microscope uses electrons accelerated by a voltage of 50kV...

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