The following table gives the values of work function far a few photosensitive metals.
`{:("S.No.","Metal","Work function (eV)"),(1.,Na,1.92),(2.,K,2.15),(3.,MO,4.17):}`
If each of these metals is exposed to radiation of wavelength 300 nm , which of them will not emit photoelectrons and why ?

Explanation

To determine which metals will not emit photoelectrons when exposed to radiation of wavelength 300 nm, we need to follow these steps:

### Step 1: Calculate the Energy of the Incident Radiation
The energy of the incident radiation can be calculated using the formula:
\[ E = \frac{hc}{\lambda} \]
where:
- \( h \) is Planck's constant (\( 6.63 \times 10^{-34} \, \text{Js} \)),
- \( c \) is the speed of light (\( 3 \times 10^{8} \, \text{m/s} \)),
...