The work function for calcium is 2.14 eV. When a light of wavelength `5500Å` is incident on it, photoelectrons are emitted , Calculate
(i) threshold frequency and threshold wavelength.
(ii) maximum velocity of the emitted electrons.
(iii) change in maximum kinetic energy of the emitted photoelectrons if the intensity of the incident light is doubled.
Take : `h = 6.6 xx10^(-34) Js m_e-9xx10^(-31) kg`
`c= 3xx10^8m//s`

Explanation

To solve the given problem step by step, we will break it down into three parts as specified in the question.

### Given Data:
- Work function for calcium, \( \phi = 2.14 \, \text{eV} \)
- Wavelength of incident light, \( \lambda = 5500 \, \text{Å} = 5500 \times 10^{-10} \, \text{m} \)
- Planck's constant, \( h = 6.6 \times 10^{-34} \, \text{Js} \)
- Speed of light, \( c = 3 \times 10^8 \, \text{m/s} \)
- Mass of electron, \( m_e = 9 \times 10^{-31} \, \text{kg} \)
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