An electron is accelerated through a potential difference of 64volts. What is the de-broglie wavelength associated with it? To which part of the electromagnetic spectrum does this value of wavelength correspond?

Explanation

Given, accelerating potential , V = 64 V
The de Broglie wavelength associated with the electron is
`lamda=(12.27)/(sqrtV)Å=(12.27)/sqrt64Å=1.53Å`
This wavelength falls in the X - ray region of electromagnetic spectrum.