The stopping potential `(v_0)` varies linearly with the frequency (v)of the incident radiation for a given photosensitive surface with the slope remaining the same for different surface . Given reason.

Explain giving reasons for the following : (a) Photoelectric current in a photocell increases with the increases in intensity of the incident radiation. (b) The stopping potential (V_0) varries linearly with the frequency (v) of the incident radiation for a given photosenstive surface with the stop remaining the same for different surfaces. (c) Maximum kinetic energy of the photoelectrons is independent of the intensity of incident radiation.

Figure show the variation of the stopping potential (V_(0)) with the frequency (v) of the incident radiations for two different photosensitive matererial M_(1) and M_(2) What are the values of work functions for M_(1) and M_(2) respectively

The slope of frequency of incident light and stopping potential for a given surface will be

The following graph shows the variation of stopping potential V_0 with the frequency v of the incident radiation for two photosensitive metals X and Y. (i) Which metal has larger threshold wavelength ? Give reason. (ii) Explain giving reason , which metal gives out electrons , having larger kinetic energy , for same wavelength of the incident radiation. (iii) If the distance between the light source and metal X is halved , how will the kinetic energy of electrons emitted from it change ? Given reason.

The stopping potential as a function of the frequency of the incident radiation is plotted for two different photoelectric surfaces A and B . The graphs show that work function of A is

The figure shows the variation of stopping potential V_(Q) with the frequency v of the incident radiations for two photosensitive metals P and Which metal has smaller threshold wavelength ? Justify your answer.