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Both the nucleus and the atom of some el...

Both the nucleus and the atom of some element are in their respective first excited states. They get de-excited by emitting photons of wavelengths `lambda_(N) ,lambda_(A)` respectively. The ratio `(lambda_(N))/(lambda_(A))` is closest to :

A

`10^(-1)`

B

`10^(-6)`

C

10

D

`10^(-10)`

Text Solution

Verified by Experts

The correct Answer is:
B
`E=(hc)/lamda`
`implieslamda_N/lamda_A=E_A/E_N`
Here, `E_A and E_N` are energies of photons from atom and nucleus respectively.
We should be aware that `E_N` is of the order of MeV and `E_A` in a few eV.
So, `lamda_N/lamda_A=(1eV)/(10^6eV)=10^(-8)`
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