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Estimate the wavelength at which plasma ...

Estimate the wavelength at which plasma reflection will occur for metal having the density of electrons `N ~~4xx10^(27)m^(-3)` . Take `epsilon_0=10^(11) and m = 10^(-30)` , where these quantities are in proper SI units.

A

800 nm

B

600 nm

C

400 nm

D

200 nm

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The correct Answer is:
To estimate the wavelength at which plasma reflection will occur for a metal with a given electron density, we can follow these steps: ### Step 1: Understand the Plasma Frequency The plasma frequency (\( \nu_p \)) is the frequency at which electrons in a plasma oscillate. It is given by the formula: \[ \nu_p = \frac{1}{2\pi} \sqrt{\frac{n e^2}{m \epsilon_0}} \] where: - \( n \) is the density of electrons (in \( m^{-3} \)), - \( e \) is the charge of an electron (\( 1.6 \times 10^{-19} \, C \)), - \( m \) is the mass of an electron (\( 9.11 \times 10^{-31} \, kg \)), - \( \epsilon_0 \) is the permittivity of free space (\( 8.85 \times 10^{-12} \, F/m \)). ### Step 2: Substitute the Values Given: - \( n = 4 \times 10^{27} \, m^{-3} \) - \( e = 1.6 \times 10^{-19} \, C \) - \( m = 10^{-30} \, kg \) (as per the question) - \( \epsilon_0 = 10^{-11} \, F/m \) (as per the question) Substituting these values into the formula for plasma frequency: \[ \nu_p = \frac{1}{2\pi} \sqrt{\frac{(4 \times 10^{27}) (1.6 \times 10^{-19})^2}{(10^{-30})(10^{-11})}} \] ### Step 3: Calculate the Plasma Frequency Calculating the numerator: \[ (1.6 \times 10^{-19})^2 = 2.56 \times 10^{-38} \] Now substituting this back: \[ \nu_p = \frac{1}{2\pi} \sqrt{\frac{(4 \times 10^{27})(2.56 \times 10^{-38})}{(10^{-30})(10^{-11})}} \] Calculating the denominator: \[ (10^{-30})(10^{-11}) = 10^{-41} \] Now substituting: \[ \nu_p = \frac{1}{2\pi} \sqrt{\frac{(4 \times 10^{27})(2.56 \times 10^{-38})}{10^{-41}}} \] \[ = \frac{1}{2\pi} \sqrt{(4 \times 2.56) \times 10^{27 + 41 - 38}} = \frac{1}{2\pi} \sqrt{10.24 \times 10^{30}} = \frac{1}{2\pi} \sqrt{10.24} \times 10^{15} \] Calculating \( \sqrt{10.24} \approx 3.2 \): \[ \nu_p \approx \frac{3.2 \times 10^{15}}{2\pi} \approx \frac{3.2 \times 10^{15}}{6.28} \approx 5.1 \times 10^{14} \, Hz \] ### Step 4: Calculate the Wavelength The wavelength (\( \lambda \)) corresponding to the plasma frequency can be calculated using the formula: \[ \lambda = \frac{c}{\nu_p} \] where \( c \) is the speed of light (\( 3 \times 10^8 \, m/s \)): \[ \lambda = \frac{3 \times 10^8}{5.1 \times 10^{14}} \approx 5.88 \times 10^{-7} \, m \] This can be converted to nanometers: \[ \lambda \approx 588 \, nm \] ### Final Answer The estimated wavelength at which plasma reflection will occur is approximately \( 588 \, nm \). ---

To estimate the wavelength at which plasma reflection will occur for a metal with a given electron density, we can follow these steps: ### Step 1: Understand the Plasma Frequency The plasma frequency (\( \nu_p \)) is the frequency at which electrons in a plasma oscillate. It is given by the formula: \[ \nu_p = \frac{1}{2\pi} \sqrt{\frac{n e^2}{m \epsilon_0}} \] where: ...
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A dence collection of equal number of electrona and positive ions is called netural plasma. Certain solids contianing fixed positive ions surroundedby free electrons can be treated as neytral plasma. Let 'N' be the numbrer density of free electrons, each of mass ' m '. When the elctrons are subjected to an eletric field, they are displaced relatively away from the heavy positive ions. if the electric field becomes zero, the electrons begin to oscillate about the positive ions with a natural angular frequency ' omega_(P)' which is called the plasma frequency. to sustain the oscillations, a time varying electric field needs to be applied that has an angular frequrncy omega , where a part of the energy is absorbed and a part of it is reflected. As omega approaches omega_(p) all the free electrons are set to resonance together and all the energy is reflected. this is the explaination of high reflectivity of metals. (2) Estimate the wavelength at which plasma reflection will occur for a metal having the density of electrons N~~ 4 xx 10^(27)m^(-3) . Taking epsilon_(0) = 10^(11) and mass m~~ 10^(-30) , where these quantities are in proper SI units.

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