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A 10kg satellite circles earth once ever...

A `10kg` satellite circles earth once every `2hr` in an orbit having a radius of `8000km`. Assuming that Bohr's angular momentum postulate applies to satellites just as it does to an electron in the hydrogen atom, find the quantum number of the orbit of the satellite.

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Given,
Mass of satellite, m=10 kg
Time period of revolution, T=2hours=2 x 60 x 60
=7200 s
Radius of orbit, r=8,000 km
`=8,000 xx 10^3` m
`=8xx10^6` m
According to the Bohr.s quantisation condition the angular momentum is given by
`L=mvr=(nh)/(2pi)`
where v=velocity of satellite
n=quantum number of satellite
`rArr (mxx2pir)/T xxr =(nh)/(2pi) " " [because v=(2pir)/T]`
`rArr n=(4pi^3r^2m)/(Th)`
`=(4xx(3.14)^2xx(8xx10^6)^2xx10)/(7200xx6.63xx10^(-34))`
`=5.28xx10^45=5.3xx10^45`
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