A potential difference of 40 kV is applied between the target metal and the filament of an X-ray tube . One electron gets accelerated through this potential difference and loses 10% of its kinetic energy in first collision. What will be the frequency of emitted photon ?

Explanation

To solve the problem step by step, we will follow the given information and apply the relevant physics concepts.

### Step 1: Calculate the kinetic energy of the electron
The kinetic energy (KE) gained by an electron when it is accelerated through a potential difference (V) is given by the formula:
\[ KE = eV \]
where:
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