Home
Class 12
PHYSICS
When a hydrogen atom emits a photon in g...

When a hydrogen atom emits a photon in going from n=5 to n=1, its recoil speed is almost

Text Solution

Verified by Experts

Wavelength of emitted photon can be written as follows :
`1/lambda=R[1/n_1^2-1/n_2^2]=(1.097xx10^7m^(-1))(1/1^2-1/5^2)`
`=1.053xx10^7 m^(-1)`
Linear momentum of photon can be written as follows :
`p=h//lambda=6.63xx10^(-34)xx1.053xx10^7=6.98xx10^(-27)` kg-m/s
When photon is emitted then according to the conservation of linear momentum hydrogen atom must also recoil with the same momentum . Let v be the speed of hydrogen atom then
`M_H xx v =6.98xx10^(-27)`
`1.67xx10^(-27)v = 6.98xx10^(-27)`
`rArr` v=4.18 m/s
Promotional Banner

Topper's Solved these Questions

  • ATOMS

    MODERN PUBLICATION|Exercise Ncert File|21 Videos
  • ATOMS

    MODERN PUBLICATION|Exercise very short|10 Videos
  • ATOMS

    MODERN PUBLICATION|Exercise Conceptual Questions|11 Videos
  • ALTERNATING CURRENT

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|16 Videos
  • CURRENT ELECTRICITY

    MODERN PUBLICATION|Exercise Chapter Practice Test|15 Videos

Similar Questions

Explore conceptually related problems

The recoil speed of a hydrogen atom after it emits a photon in going from n=5 , state to n=1 state is (in ms^(-1) )

The recoil speed of a hydrogen atom after it emits a photon is going form n=5 state to n =1 state is ….. m/s.

Whenever a hydrogen atom emits a photon in the Balmer series

The recoil speed of hydrogen atom after it emits a photon in going from n = 2 state to n = 1 state is nearly [Take R_(oo) = 1.1 xx 10^(7) m and h = 6.63 xx 10^(-34) J s]

Whenever a hydrogen atom emits a photon in the Balmer series .

Whenever a hydrogen atom emits photon in the Balmer series: