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Would the Bohr formula for the H-atom re...

Would the Bohr formula for the H-atom remain unchanged if proton had a charge `(+4//3) e` and electron a charge `(-3//4) e`, where `e = 1.6 xx 10^(-19) C`. Given reasons for you answer.

Text Solution

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Yes, the formula will remain unchanged. This is because the centripetal force `(F_e=(mv^2)/r)` is provided by Coulomb.s force between the proton and electron. Also, Coulomb.s force is given by
`F_e=(Ke^2)/r^2` (Charge on proton =e , Charge on electron =-e)
The Coulomb.s force is proportional to `e^2`
Now, if the charge on proton `((+4)/3e)` and magnitude of charge on electron is `(3/4e)`, then their product, `[(4/3e)xx(3/4e)]=e^2`, remains unchanged.
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