For an electron in the second orbit of hydrogen, the angular momentum as per the Bohr's model is

Options

A. 2h
B. h
C. `h/pi`
D. `(2h)/pi`

Answer

To find the angular momentum of an electron in the second orbit of hydrogen according to Bohr's model, we can follow these steps:

### Step 1: Understand the formula for angular momentum in Bohr's model
According to Bohr's model, the angular momentum (L) of an electron in a stationary orbit is given by the formula:
\[ L = n \frac{h}{2\pi} \]
where:
- \( L \) is the angular momentum,
- \( n \) is the principal quantum number (orbit number),
- \( h \) is Planck's constant.

### Step 2: Identify the value of \( n \)
For the second orbit of hydrogen, the principal quantum number \( n \) is 2.

### Step 3: Substitute the value of \( n \) into the formula
Now, we substitute \( n = 2 \) into the angular momentum formula:
\[ L = 2 \frac{h}{2\pi} \]

### Step 4: Simplify the expression
Now we can simplify the expression:
\[ L = \frac{2h}{2\pi} = \frac{h}{\pi} \]

### Step 5: Conclusion
Thus, the angular momentum of an electron in the second orbit of hydrogen according to Bohr's model is:
\[ L = \frac{h}{\pi} \]

### Final Answer
The angular momentum for an electron in the second orbit of hydrogen is \( \frac{h}{\pi} \).

---