Find the distance of closest approach when a 6 MeV proton approaches a gold nucleus.

Explanation

To find the distance of closest approach when a 6 MeV proton approaches a gold nucleus, we can follow these steps:

### Step 1: Identify the Charges
The gold nucleus has an atomic number \( Z = 79 \), which means it has a charge of \( Q_{\text{gold}} = 79e \), where \( e \) is the elementary charge (\( e = 1.6 \times 10^{-19} \, \text{C} \)). The proton has a charge of \( Q_{\text{proton}} = e \).

### Step 2: Write the Formula for Distance of Closest Approach
The distance of closest approach \( R_{\text{min}} \) can be calculated using the formula:
\[
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