The natural lithium is composed of two isotopes of `""_(3)Li^(6)` and `""_(3)Li^(7)`. The isotopes have masses 6.015121 amu and 7.016003 amu, respectively. Calculate the relative abundance of each isotope in the natural lithium if the atomic mass of natural lithium is 6.94 amu.

Explanation

To solve the problem of finding the relative abundance of the isotopes of lithium, we can follow these steps:

### Step 1: Define Variables
Let:
- \( x \) = relative abundance of \( ^6Li \) (in percentage)
- \( 100 - x \) = relative abundance of \( ^7Li \) (in percentage)

### Step 2: Write the Equation for Average Atomic Mass
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