Calculate the binding energy per nucleon in the nuclei of `._(15)P^(31)`. Given `m(._(15)P^(31))=30.97376u, m(._(0)n^(1))=1.00865 u, m(._(1)H^(1))=1.00782u`.

Explanation

Nucleus of `""_(15)P^(31)` contains 15 protons and 16 neutrons.
Mass of 15 protons = `15 xx 1.00782 = 15.1173` amu
Mass of 16 neutrons = `16 xx 1.00865 = 16.1384` amu
Total mass of protons and neutrons
`=(15.1173 + 16.1384)` amu
=31.2557 amu
Mass of `""_(15)P^(31)` nucleus = 30.97376 amu
Mass defect, `Deltam = (31.2557 - 30.97376)` amu
=0.28194 amu
Binding energy of `""_(15)P^(31)` nucleus is
`DeltaE = Deltam = 931 MeV`
`=0.28194 xx 931 = 262.486` MeV