The half-life of `""_(54)Po^(210)` is 140 days. What amount of `""_(54)Po^(210)` is required to provide source of a-particles of 10 mCi strength?

Explanation

To find the amount of Polonium-210 (Po-210) required to provide a source of alpha particles of 10 mCi strength, we can follow these steps:

### Step 1: Convert the activity from mCi to disintegrations per second (dps)
1 mCi (millicurie) is equivalent to \(3.7 \times 10^{7}\) disintegrations per second (dps). Therefore, for 10 mCi:
\[ \text{Activity (A)} = 10 \, \text{mCi} \times 3.7 \times 10^{7} \, \text{dps/mCi} = 3.7 \times 10^{8} \, \text{dps} \]

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