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Calculate the disintegration energy Q fo...

Calculate the disintegration energy Q for fission of `._42Mo^(98)` into two equal fragments `._21Sc^(49)` by bombarding with a neutron. Given that
`m(._42Mo^(98))=97.90541u, m(._21Sc^(49))=48.95002u, m_n=1.00867u`

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The given fission reaction is
`""_(42)Mo^(98) + ""_(0)n^(1) to 2_(21)Sc^(49) + Q`
The energy released in the fission reaction is
`Q = [m(""_(42)Mo^(98) ) +m_(n) -2m(""_(21)Sc^(49))]c^(2)`
`=(97.90541 + 1.00867 - 2 xx 48.95002) amu xx c^(2)`
`=1.01404 xx 931.5 MeV = 944.6 MeV`
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MODERN PUBLICATION-NUCLEI-CHAPTER PRACTICE TEST FOR BOARD EXAMINATION
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