What is the energy released by fassion of 1 g of `U^(235)`? (Assume 200 Me V energy is liberated on fission of 1 nucleus)

Explanation

Number of atoms in 235 g of `""_(92)U^(235)`
= Avogadro.s number `=6.023 xx 10^(23)`
Number of atoms in 1 g of `""_(92)U^(235) = (6.023 xx 10^(23))/235 xx 10`
`=(6.023 xx 10^(24))/235`
Energy released per fission = 200 MeV
`therefore` Energy released by fission of 10 g of `""_(92)U^(235)`
`=(6.023 xx 10^(24))/235 xx 200` MeV
`= 5.126 xx 10^(24)` MeV
`=2.28 xx 10^(5) kWh`