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Obtain the binding energy (in MeV) of a ...

Obtain the binding energy (in MeV) of a nitrogen nucleus `(""_(7)^(14)N)` , given `m(""_(7)^(14)N)`
`=14.00307" "u`

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The correct Answer is:
7.472 MeV/nucleon
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Obtain the binding energy of a nitrogen nucleus from the following data: m_H=1.00783u ,m_N=1.00867u ,m( _7^14N)=14.00307u Give your answer in units of MeV. [Remember 1u=931.5MeV//c^2 ]

The binding energy per nucleon of ""_(7)N^(14) nucleus is: (Mass of ""_(7)N^(14) = 14.00307 u ) mass of proton = 1.007825 u mass of neutron = 1.008665 u

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What name is given to the pair of atoms such as ._(7)^(14) N and ._(7)^(15)N ?

What is the binding energy per nucleon of _(6)C^(12) nucleus? Given , mass of C^(12) (m_(c))_(m) = 12.000 u Mass of proton m_(p) = 1.0078 u Mass of neutron m_(n) = 1.0087 u and 1 amu = 931.4 MeV

Making use of the table of atomic masses given above find: (a) the mean binding energy per nucleon in ._(7)^(14)N (b) the binding energy of an alpha-particle in ._(8)^(16)O .

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Using the following data .Mass hydrogen atom = 1.00783 u Mass of neutron = 1.00867 u Mass of nitrogen atom (._7N^(14)) 14.00307 u The calculated value of the binding energy of the nucleus of the nitrogen atom (._7 N^(14)) is close to

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