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By using the following atomic masses : `._(92)^(238)U = 238.05079u`. `._(2)^(4)He = 4.00260u, ._(90)^(234)Th = 234.04363u`.
`._(1)^(1)H = 1.007834, ._(91)^(237)Pa = 237.065121u` (i) Calculate the energy released during the `alpha-`decay of `._(92)^(238)U`.
(ii) Show that `._(92)^(238)U` cannot spontaneously emit a proton.

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The correct Answer is:
4.25 MeV
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We are given the following atomic masses: ._(92)^(238)U=238.05079u ._(2)^(4)He=4.00260u ._(90)^(234)Th=234.04363u ._(1)^(1)H=1.00783u ._(91)^(237)Pa=237.05121u Here the symbol Pa is for the element protactinium (Z=91)

We are given the following atomic masses: ._92Pu^(238)=238.05079u, ._90Th^(234)=234.04363u , ._91Pa^(237)=237.05121, ._1H^1=1.00783 , ._2He^2=4.00260u (a) Calculate the energy released during alpha decay of ._92U^(238) , (b) Calculate the kinetic energy of emitted alpha particles, (c) show that ._94Pu^(238) cannot spontaneously emit a proton.

We are given the following atomic masses: ""_(93)Pu^(238) = 238.04954 u ""_(92)U^(234) = 234.04096 u ""_(2)He^(4) = 4.00260 u Calculate the kinetic energy associated with the alpha particle emitted during the conversion of ""_(94)Pu^(238) into ""_(92)U^(234)

The atomic mass of uranium ._(92)^(238)U is 23.058 u , that of throium ._(90)^(234)Th is 234.0436 u and that of an alpha particle ._2^4He is 4.006 u , Determine the energy released when alpha-decay converts ._(92)^(238)U into ._(92)^(238) U . int ._(90)^(234)Th .

What are the numbers of protons and neutrons in the nucleus of ._92U^(238) ?

Calculate the number of alpha - and beta -particles emitted when ._(92)U^(238) into radioactive ._(82)Pb^(206) .

Show that ""_(92)^(238)U can not spontaneously emit a proton. Given: ""_(92)^(238)U = 238.05079u, ""_(91)^(237)Pa = 237.05121u ""_(1)^(1)H = 1.00783u

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