Calculate the energy released in MeV dur...

Calculate the energy released in MeV during the reaction `._(3)^(7)Li + ._(1)^(1)H to 2[._(2)^(4)He]` if the masses of `._(3)^(7)Li, ._(1)^(1)H` and `._(2)H_(4)He` are 7.018, 1.008 and 4.004 amu respectively.

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The correct Answer is:

14.904 MeV

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Calcualte the energy released (in joule and MeV ) in the follwing nulcear reaction: ._(1)^(2)H + ._(1)^(2)H rarr ._(2)^(3)He + ._(0)^(1)n Assume that the masses of ._(1)^(2)H, ._(2)^(3)He and neutron (n) are 2.0141,3.0160 and 1.0087 respectively in amu.

Calculate the energy released in joules and MeV in the following nuclear reaction: ._(1)H^(2) + ._(1)H^(2) rarr ._(2)He^(3) + ._(0)n^(1) Assume that the masses of ._(1)H^(2) , ._(2)He^(3) , and neutron (n) , respectively, are 2.40, 3.0160, and 1.0087 in amu.

Calculate the mass loss in the following: ._(1)^(2)H + ._(1)^(3)H to ._(2)^(4)He + ._(0)^(1)n given the masses: ._(1)^(2)H = 2.014 amu, ._(1)^(3)H = 3.016 amu: ._(2)^(4)He = 4.004 amu, ._(0)^(1)n = 008 amu

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