A nucleus with mass number A =240 and BE`//`A = 7.6 Me V breaks into two fragments each of A =120 with `BE//A ` =8.5 Me V .Calculate the released energy .

Explanation

Binding energy of nuclear with mass number 240, `B_(1) = 7.6 xx 240 = 1,824` MeV
Binding energy of nucleus of each fragment, `B_(2) = 8.5 xx 120 = 1,020` MeV
Energy released is given by `E = 2B_(2) - B_(1) = 2 xx 1,0200 - 1,824 = 216 MeV`