Is it possible for `""_(92)U^(238)` spontaneously to emit a proton? Given, atomic mass of `""_(92)U^(238), ""_(91)Pa^(237)` and `""_(1)H^(1)` is 238.05079 u, 237.05115 u and 1.00783 u respectively.

Explanation

To determine if Uranium-238 (U-238) can spontaneously emit a proton, we need to analyze the reaction and calculate the Q-value (energy released) for the reaction. Here’s how we can do this step by step:

### Step 1: Write the Reaction
The reaction for the emission of a proton from U-238 can be represented as:
\[ _{92}^{238}U \rightarrow _{91}^{237}Pa + _{1}^{1}H \]
Where U-238 emits a proton (H-1) and transforms into Protactinium-237 (Pa-237).
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