A given coin has a mass of 3.0 g. Calculate the nuclear energy that would be required to separated all the neutrons and protons form each other. for simplicity, assume that the coin is entirely made of `._29Cu^(63)` atoms (of mass 62.92960 u).

Explanation

Here, atomic number, Z=29
Mass number A = 63,
So, number of neutrons, N=A-Z = 34
Given, `m(""_(29)Cu^(63)), M=62.92960` u
Mass defect
`Deltam =(Zm_(H) +(Nm-(n)-M)`
`=(29 xx 1.00783 + 34 xx 1.00867 - 62.92960)-0.592254`u
Since, `1u = 931.5 MeV//c^(2)`
B.E. `""_(29)Cu^(63)`
`=Deltamc^(2) = 0.592254 xx 931.5 MeV`
`=551.68` MeV
Since 63 g of `""_(29)Cu^(63)` contains `6.023 xx 10^(23)` atoms. So
3g of `""_(29)Cu^(63)` contains `(3 xx 6.023 xx 10^(23))/63 = 2.868 xx 10^(22)` atoms.
`therefore` total energy required to separate neutrons and protons from each other of 3.0 g Cu is
`E = 2.868 xx 10^(22) xx 551.68`
`=1.58 xx 10^(25)`
`=1.58 xx 10^(25) xx 1.6 xx 10^(-13)J = 2.52 xx 10^(12)` J